Integrand size = 27, antiderivative size = 399 \[ \int \frac {\cos ^5(c+d x) \cot (c+d x)}{(a+b \sin (c+d x))^3} \, dx=-\frac {x}{2 b^3}-\frac {3 \left (2 a^2-b^2\right ) x}{b^5}+\frac {\sqrt {a^2-b^2} \left (2 a^2+b^2\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a b^5 d}-\frac {2 \sqrt {a^2-b^2} \left (5 a^2+b^2\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a b^5 d}+\frac {2 \left (10 a^6-9 a^4 b^2-b^6\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a^3 b^5 \sqrt {a^2-b^2} d}-\frac {\text {arctanh}(\cos (c+d x))}{a^3 d}-\frac {3 a \cos (c+d x)}{b^4 d}+\frac {\cos (c+d x) \sin (c+d x)}{2 b^3 d}+\frac {\left (a^2-b^2\right )^2 \cos (c+d x)}{2 a b^4 d (a+b \sin (c+d x))^2}+\frac {3 \left (a^2-b^2\right ) \cos (c+d x)}{2 b^4 d (a+b \sin (c+d x))}-\frac {\left (a^2-b^2\right ) \left (5 a^2+b^2\right ) \cos (c+d x)}{a^2 b^4 d (a+b \sin (c+d x))} \]
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Time = 0.39 (sec) , antiderivative size = 399, normalized size of antiderivative = 1.00, number of steps used = 20, number of rules used = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.407, Rules used = {2976, 3855, 2718, 2715, 8, 2743, 2833, 12, 2739, 632, 210} \[ \int \frac {\cos ^5(c+d x) \cot (c+d x)}{(a+b \sin (c+d x))^3} \, dx=-\frac {\text {arctanh}(\cos (c+d x))}{a^3 d}+\frac {\left (2 a^2+b^2\right ) \sqrt {a^2-b^2} \arctan \left (\frac {a \tan \left (\frac {1}{2} (c+d x)\right )+b}{\sqrt {a^2-b^2}}\right )}{a b^5 d}-\frac {2 \left (5 a^2+b^2\right ) \sqrt {a^2-b^2} \arctan \left (\frac {a \tan \left (\frac {1}{2} (c+d x)\right )+b}{\sqrt {a^2-b^2}}\right )}{a b^5 d}-\frac {3 x \left (2 a^2-b^2\right )}{b^5}+\frac {\left (a^2-b^2\right )^2 \cos (c+d x)}{2 a b^4 d (a+b \sin (c+d x))^2}-\frac {\left (5 a^2+b^2\right ) \left (a^2-b^2\right ) \cos (c+d x)}{a^2 b^4 d (a+b \sin (c+d x))}+\frac {3 \left (a^2-b^2\right ) \cos (c+d x)}{2 b^4 d (a+b \sin (c+d x))}+\frac {2 \left (10 a^6-9 a^4 b^2-b^6\right ) \arctan \left (\frac {a \tan \left (\frac {1}{2} (c+d x)\right )+b}{\sqrt {a^2-b^2}}\right )}{a^3 b^5 d \sqrt {a^2-b^2}}-\frac {3 a \cos (c+d x)}{b^4 d}+\frac {\sin (c+d x) \cos (c+d x)}{2 b^3 d}-\frac {x}{2 b^3} \]
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Rule 8
Rule 12
Rule 210
Rule 632
Rule 2715
Rule 2718
Rule 2739
Rule 2743
Rule 2833
Rule 2976
Rule 3855
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {3 \left (-2 a^2+b^2\right )}{b^5}+\frac {\csc (c+d x)}{a^3}+\frac {3 a \sin (c+d x)}{b^4}-\frac {\sin ^2(c+d x)}{b^3}+\frac {\left (a^2-b^2\right )^3}{a b^5 (a+b \sin (c+d x))^3}-\frac {\left (a^2-b^2\right )^2 \left (5 a^2+b^2\right )}{a^2 b^5 (a+b \sin (c+d x))^2}+\frac {10 a^6-9 a^4 b^2-b^6}{a^3 b^5 (a+b \sin (c+d x))}\right ) \, dx \\ & = -\frac {3 \left (2 a^2-b^2\right ) x}{b^5}+\frac {\int \csc (c+d x) \, dx}{a^3}+\frac {(3 a) \int \sin (c+d x) \, dx}{b^4}-\frac {\int \sin ^2(c+d x) \, dx}{b^3}+\frac {\left (a^2-b^2\right )^3 \int \frac {1}{(a+b \sin (c+d x))^3} \, dx}{a b^5}-\frac {\left (\left (a^2-b^2\right )^2 \left (5 a^2+b^2\right )\right ) \int \frac {1}{(a+b \sin (c+d x))^2} \, dx}{a^2 b^5}+\frac {\left (10 a^6-9 a^4 b^2-b^6\right ) \int \frac {1}{a+b \sin (c+d x)} \, dx}{a^3 b^5} \\ & = -\frac {3 \left (2 a^2-b^2\right ) x}{b^5}-\frac {\text {arctanh}(\cos (c+d x))}{a^3 d}-\frac {3 a \cos (c+d x)}{b^4 d}+\frac {\cos (c+d x) \sin (c+d x)}{2 b^3 d}+\frac {\left (a^2-b^2\right )^2 \cos (c+d x)}{2 a b^4 d (a+b \sin (c+d x))^2}-\frac {\left (a^2-b^2\right ) \left (5 a^2+b^2\right ) \cos (c+d x)}{a^2 b^4 d (a+b \sin (c+d x))}-\frac {\int 1 \, dx}{2 b^3}-\frac {\left (a^2-b^2\right )^2 \int \frac {-2 a+b \sin (c+d x)}{(a+b \sin (c+d x))^2} \, dx}{2 a b^5}+\frac {\left (\left (a^2-b^2\right )^2 \left (5 a^2+b^2\right )\right ) \int \frac {a}{a+b \sin (c+d x)} \, dx}{a^2 b^5 \left (-a^2+b^2\right )}+\frac {\left (2 \left (10 a^6-9 a^4 b^2-b^6\right )\right ) \text {Subst}\left (\int \frac {1}{a+2 b x+a x^2} \, dx,x,\tan \left (\frac {1}{2} (c+d x)\right )\right )}{a^3 b^5 d} \\ & = -\frac {x}{2 b^3}-\frac {3 \left (2 a^2-b^2\right ) x}{b^5}-\frac {\text {arctanh}(\cos (c+d x))}{a^3 d}-\frac {3 a \cos (c+d x)}{b^4 d}+\frac {\cos (c+d x) \sin (c+d x)}{2 b^3 d}+\frac {\left (a^2-b^2\right )^2 \cos (c+d x)}{2 a b^4 d (a+b \sin (c+d x))^2}+\frac {3 \left (a^2-b^2\right ) \cos (c+d x)}{2 b^4 d (a+b \sin (c+d x))}-\frac {\left (a^2-b^2\right ) \left (5 a^2+b^2\right ) \cos (c+d x)}{a^2 b^4 d (a+b \sin (c+d x))}+\frac {\left (a^2-b^2\right ) \int \frac {2 a^2+b^2}{a+b \sin (c+d x)} \, dx}{2 a b^5}+\frac {\left (\left (a^2-b^2\right )^2 \left (5 a^2+b^2\right )\right ) \int \frac {1}{a+b \sin (c+d x)} \, dx}{a b^5 \left (-a^2+b^2\right )}-\frac {\left (4 \left (10 a^6-9 a^4 b^2-b^6\right )\right ) \text {Subst}\left (\int \frac {1}{-4 \left (a^2-b^2\right )-x^2} \, dx,x,2 b+2 a \tan \left (\frac {1}{2} (c+d x)\right )\right )}{a^3 b^5 d} \\ & = -\frac {x}{2 b^3}-\frac {3 \left (2 a^2-b^2\right ) x}{b^5}+\frac {2 \left (10 a^6-9 a^4 b^2-b^6\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a^3 b^5 \sqrt {a^2-b^2} d}-\frac {\text {arctanh}(\cos (c+d x))}{a^3 d}-\frac {3 a \cos (c+d x)}{b^4 d}+\frac {\cos (c+d x) \sin (c+d x)}{2 b^3 d}+\frac {\left (a^2-b^2\right )^2 \cos (c+d x)}{2 a b^4 d (a+b \sin (c+d x))^2}+\frac {3 \left (a^2-b^2\right ) \cos (c+d x)}{2 b^4 d (a+b \sin (c+d x))}-\frac {\left (a^2-b^2\right ) \left (5 a^2+b^2\right ) \cos (c+d x)}{a^2 b^4 d (a+b \sin (c+d x))}+\frac {\left (\left (a^2-b^2\right ) \left (2 a^2+b^2\right )\right ) \int \frac {1}{a+b \sin (c+d x)} \, dx}{2 a b^5}+\frac {\left (2 \left (a^2-b^2\right )^2 \left (5 a^2+b^2\right )\right ) \text {Subst}\left (\int \frac {1}{a+2 b x+a x^2} \, dx,x,\tan \left (\frac {1}{2} (c+d x)\right )\right )}{a b^5 \left (-a^2+b^2\right ) d} \\ & = -\frac {x}{2 b^3}-\frac {3 \left (2 a^2-b^2\right ) x}{b^5}+\frac {2 \left (10 a^6-9 a^4 b^2-b^6\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a^3 b^5 \sqrt {a^2-b^2} d}-\frac {\text {arctanh}(\cos (c+d x))}{a^3 d}-\frac {3 a \cos (c+d x)}{b^4 d}+\frac {\cos (c+d x) \sin (c+d x)}{2 b^3 d}+\frac {\left (a^2-b^2\right )^2 \cos (c+d x)}{2 a b^4 d (a+b \sin (c+d x))^2}+\frac {3 \left (a^2-b^2\right ) \cos (c+d x)}{2 b^4 d (a+b \sin (c+d x))}-\frac {\left (a^2-b^2\right ) \left (5 a^2+b^2\right ) \cos (c+d x)}{a^2 b^4 d (a+b \sin (c+d x))}+\frac {\left (\left (a^2-b^2\right ) \left (2 a^2+b^2\right )\right ) \text {Subst}\left (\int \frac {1}{a+2 b x+a x^2} \, dx,x,\tan \left (\frac {1}{2} (c+d x)\right )\right )}{a b^5 d}+\frac {\left (4 \left (a^2-b^2\right ) \left (5 a^2+b^2\right )\right ) \text {Subst}\left (\int \frac {1}{-4 \left (a^2-b^2\right )-x^2} \, dx,x,2 b+2 a \tan \left (\frac {1}{2} (c+d x)\right )\right )}{a b^5 d} \\ & = -\frac {x}{2 b^3}-\frac {3 \left (2 a^2-b^2\right ) x}{b^5}-\frac {2 \sqrt {a^2-b^2} \left (5 a^2+b^2\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a b^5 d}+\frac {2 \left (10 a^6-9 a^4 b^2-b^6\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a^3 b^5 \sqrt {a^2-b^2} d}-\frac {\text {arctanh}(\cos (c+d x))}{a^3 d}-\frac {3 a \cos (c+d x)}{b^4 d}+\frac {\cos (c+d x) \sin (c+d x)}{2 b^3 d}+\frac {\left (a^2-b^2\right )^2 \cos (c+d x)}{2 a b^4 d (a+b \sin (c+d x))^2}+\frac {3 \left (a^2-b^2\right ) \cos (c+d x)}{2 b^4 d (a+b \sin (c+d x))}-\frac {\left (a^2-b^2\right ) \left (5 a^2+b^2\right ) \cos (c+d x)}{a^2 b^4 d (a+b \sin (c+d x))}-\frac {\left (2 \left (a^2-b^2\right ) \left (2 a^2+b^2\right )\right ) \text {Subst}\left (\int \frac {1}{-4 \left (a^2-b^2\right )-x^2} \, dx,x,2 b+2 a \tan \left (\frac {1}{2} (c+d x)\right )\right )}{a b^5 d} \\ & = -\frac {x}{2 b^3}-\frac {3 \left (2 a^2-b^2\right ) x}{b^5}+\frac {\sqrt {a^2-b^2} \left (2 a^2+b^2\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a b^5 d}-\frac {2 \sqrt {a^2-b^2} \left (5 a^2+b^2\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a b^5 d}+\frac {2 \left (10 a^6-9 a^4 b^2-b^6\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a^3 b^5 \sqrt {a^2-b^2} d}-\frac {\text {arctanh}(\cos (c+d x))}{a^3 d}-\frac {3 a \cos (c+d x)}{b^4 d}+\frac {\cos (c+d x) \sin (c+d x)}{2 b^3 d}+\frac {\left (a^2-b^2\right )^2 \cos (c+d x)}{2 a b^4 d (a+b \sin (c+d x))^2}+\frac {3 \left (a^2-b^2\right ) \cos (c+d x)}{2 b^4 d (a+b \sin (c+d x))}-\frac {\left (a^2-b^2\right ) \left (5 a^2+b^2\right ) \cos (c+d x)}{a^2 b^4 d (a+b \sin (c+d x))} \\ \end{align*}
Time = 1.71 (sec) , antiderivative size = 243, normalized size of antiderivative = 0.61 \[ \int \frac {\cos ^5(c+d x) \cot (c+d x)}{(a+b \sin (c+d x))^3} \, dx=\frac {\frac {2 \left (-12 a^2+5 b^2\right ) (c+d x)}{b^5}+\frac {4 \left (12 a^6-11 a^4 b^2+a^2 b^4-2 b^6\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a^3 b^5 \sqrt {a^2-b^2}}-\frac {12 a \cos (c+d x)}{b^4}-\frac {4 \log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right )}{a^3}+\frac {4 \log \left (\sin \left (\frac {1}{2} (c+d x)\right )\right )}{a^3}+\frac {2 \left (a^2-b^2\right )^2 \cos (c+d x)}{a b^4 (a+b \sin (c+d x))^2}+\frac {2 \left (-7 a^4+5 a^2 b^2+2 b^4\right ) \cos (c+d x)}{a^2 b^4 (a+b \sin (c+d x))}+\frac {\sin (2 (c+d x))}{b^3}}{4 d} \]
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Time = 2.34 (sec) , antiderivative size = 359, normalized size of antiderivative = 0.90
method | result | size |
derivativedivides | \(\frac {\frac {\ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a^{3}}-\frac {2 \left (\frac {\frac {\left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) b^{2}}{2}+3 \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a b -\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right ) b^{2}}{2}+3 a b}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{2}}+\frac {\left (12 a^{2}-5 b^{2}\right ) \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2}\right )}{b^{5}}+\frac {\frac {2 \left (\left (-\frac {5}{2} a^{5} b^{2}+\frac {1}{2} a^{3} b^{4}+2 a \,b^{6}\right ) \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-\frac {3 b \left (2 a^{6}+3 a^{4} b^{2}-3 a^{2} b^{4}-2 b^{6}\right ) \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2}-\frac {a \,b^{2} \left (19 a^{4}-11 a^{2} b^{2}-8 b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{2}-\frac {3 a^{2} b \left (2 a^{4}-a^{2} b^{2}-b^{4}\right )}{2}\right )}{{\left (\left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a +2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+a \right )}^{2}}+\frac {\left (12 a^{6}-11 a^{4} b^{2}+a^{2} b^{4}-2 b^{6}\right ) \arctan \left (\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+2 b}{2 \sqrt {a^{2}-b^{2}}}\right )}{\sqrt {a^{2}-b^{2}}}}{a^{3} b^{5}}}{d}\) | \(359\) |
default | \(\frac {\frac {\ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a^{3}}-\frac {2 \left (\frac {\frac {\left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) b^{2}}{2}+3 \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a b -\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right ) b^{2}}{2}+3 a b}{\left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{2}}+\frac {\left (12 a^{2}-5 b^{2}\right ) \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2}\right )}{b^{5}}+\frac {\frac {2 \left (\left (-\frac {5}{2} a^{5} b^{2}+\frac {1}{2} a^{3} b^{4}+2 a \,b^{6}\right ) \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-\frac {3 b \left (2 a^{6}+3 a^{4} b^{2}-3 a^{2} b^{4}-2 b^{6}\right ) \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2}-\frac {a \,b^{2} \left (19 a^{4}-11 a^{2} b^{2}-8 b^{4}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{2}-\frac {3 a^{2} b \left (2 a^{4}-a^{2} b^{2}-b^{4}\right )}{2}\right )}{{\left (\left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a +2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+a \right )}^{2}}+\frac {\left (12 a^{6}-11 a^{4} b^{2}+a^{2} b^{4}-2 b^{6}\right ) \arctan \left (\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+2 b}{2 \sqrt {a^{2}-b^{2}}}\right )}{\sqrt {a^{2}-b^{2}}}}{a^{3} b^{5}}}{d}\) | \(359\) |
risch | \(-\frac {6 x \,a^{2}}{b^{5}}+\frac {5 x}{2 b^{3}}-\frac {i {\mathrm e}^{2 i \left (d x +c \right )}}{8 b^{3} d}-\frac {3 a \,{\mathrm e}^{i \left (d x +c \right )}}{2 b^{4} d}-\frac {3 a \,{\mathrm e}^{-i \left (d x +c \right )}}{2 b^{4} d}+\frac {i {\mathrm e}^{-2 i \left (d x +c \right )}}{8 b^{3} d}+\frac {i \left (-8 i a^{5} b \,{\mathrm e}^{3 i \left (d x +c \right )}+7 i a^{3} b^{3} {\mathrm e}^{3 i \left (d x +c \right )}+i a \,b^{5} {\mathrm e}^{3 i \left (d x +c \right )}+20 i a^{5} b \,{\mathrm e}^{i \left (d x +c \right )}-13 i a^{3} b^{3} {\mathrm e}^{i \left (d x +c \right )}-7 i a \,b^{5} {\mathrm e}^{i \left (d x +c \right )}+14 a^{6} {\mathrm e}^{2 i \left (d x +c \right )}-3 a^{4} b^{2} {\mathrm e}^{2 i \left (d x +c \right )}-9 a^{2} b^{4} {\mathrm e}^{2 i \left (d x +c \right )}-2 b^{6} {\mathrm e}^{2 i \left (d x +c \right )}-7 a^{4} b^{2}+5 a^{2} b^{4}+2 b^{6}\right )}{\left (-i b \,{\mathrm e}^{2 i \left (d x +c \right )}+i b +2 a \,{\mathrm e}^{i \left (d x +c \right )}\right )^{2} a^{2} d \,b^{5}}+\frac {6 i \sqrt {a^{2}-b^{2}}\, a \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i \left (\sqrt {a^{2}-b^{2}}+a \right )}{b}\right )}{d \,b^{5}}+\frac {i \sqrt {a^{2}-b^{2}}\, \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i \left (\sqrt {a^{2}-b^{2}}+a \right )}{b}\right )}{2 d \,b^{3} a}+\frac {i \sqrt {a^{2}-b^{2}}\, \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i \left (\sqrt {a^{2}-b^{2}}+a \right )}{b}\right )}{d b \,a^{3}}-\frac {6 i \sqrt {a^{2}-b^{2}}\, a \ln \left ({\mathrm e}^{i \left (d x +c \right )}-\frac {i \left (\sqrt {a^{2}-b^{2}}-a \right )}{b}\right )}{d \,b^{5}}-\frac {i \sqrt {a^{2}-b^{2}}\, \ln \left ({\mathrm e}^{i \left (d x +c \right )}-\frac {i \left (\sqrt {a^{2}-b^{2}}-a \right )}{b}\right )}{2 d \,b^{3} a}-\frac {i \sqrt {a^{2}-b^{2}}\, \ln \left ({\mathrm e}^{i \left (d x +c \right )}-\frac {i \left (\sqrt {a^{2}-b^{2}}-a \right )}{b}\right )}{d b \,a^{3}}+\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}-1\right )}{d \,a^{3}}-\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )}{d \,a^{3}}\) | \(676\) |
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Time = 0.72 (sec) , antiderivative size = 1007, normalized size of antiderivative = 2.52 \[ \int \frac {\cos ^5(c+d x) \cot (c+d x)}{(a+b \sin (c+d x))^3} \, dx=\text {Too large to display} \]
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\[ \int \frac {\cos ^5(c+d x) \cot (c+d x)}{(a+b \sin (c+d x))^3} \, dx=\int \frac {\cos ^{6}{\left (c + d x \right )} \csc {\left (c + d x \right )}}{\left (a + b \sin {\left (c + d x \right )}\right )^{3}}\, dx \]
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Exception generated. \[ \int \frac {\cos ^5(c+d x) \cot (c+d x)}{(a+b \sin (c+d x))^3} \, dx=\text {Exception raised: ValueError} \]
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Time = 0.36 (sec) , antiderivative size = 635, normalized size of antiderivative = 1.59 \[ \int \frac {\cos ^5(c+d x) \cot (c+d x)}{(a+b \sin (c+d x))^3} \, dx=\frac {\frac {2 \, \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) \right |}\right )}{a^{3}} - \frac {{\left (12 \, a^{2} - 5 \, b^{2}\right )} {\left (d x + c\right )}}{b^{5}} + \frac {2 \, {\left (12 \, a^{6} - 11 \, a^{4} b^{2} + a^{2} b^{4} - 2 \, b^{6}\right )} {\left (\pi \left \lfloor \frac {d x + c}{2 \, \pi } + \frac {1}{2} \right \rfloor \mathrm {sgn}\left (a\right ) + \arctan \left (\frac {a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + b}{\sqrt {a^{2} - b^{2}}}\right )\right )}}{\sqrt {a^{2} - b^{2}} a^{3} b^{5}} - \frac {2 \, {\left (6 \, a^{5} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - a^{3} b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 4 \, a b^{5} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 12 \, a^{6} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{6} + 13 \, a^{4} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{6} - 9 \, a^{2} b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{6} - 6 \, b^{6} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{6} + 54 \, a^{5} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 9 \, a^{3} b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 16 \, a b^{5} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 36 \, a^{6} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 39 \, a^{4} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 21 \, a^{2} b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} - 12 \, b^{6} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 90 \, a^{5} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 27 \, a^{3} b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 20 \, a b^{5} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 36 \, a^{6} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 23 \, a^{4} b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 15 \, a^{2} b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 6 \, b^{6} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 42 \, a^{5} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 11 \, a^{3} b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 8 \, a b^{5} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 12 \, a^{6} - 3 \, a^{4} b^{2} - 3 \, a^{2} b^{4}\right )}}{{\left (a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{4} + 2 \, b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 2 \, a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 2 \, b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + a\right )}^{2} a^{3} b^{4}}}{2 \, d} \]
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Time = 14.30 (sec) , antiderivative size = 5354, normalized size of antiderivative = 13.42 \[ \int \frac {\cos ^5(c+d x) \cot (c+d x)}{(a+b \sin (c+d x))^3} \, dx=\text {Too large to display} \]
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